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中文姓名遮罩和判斷字串有中英文方法

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網路收集幾個方法

判斷中英文方法

判断字符串是否纯中文、英文、数字、等等_心丨悦 的专栏-CSDN博客

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public void isEnglish(String str) {
    //【全为英文】返回true  否则false
    boolean result1 = str.matches("[a-zA-Z]+");
    //【全为数字】返回true
    boolean result6 = str.matches("[0-9]+");
    //【除英文和数字外无其他字符(只有英文数字的字符串)】返回true 否则false
    boolean result2 = str.matches("[a-zA-Z0-9]+");
    //【含有英文】true
    String regex1 = ".*[a-zA-z].*";
    boolean result3 = str.matches(regex1);
    //【含有数字】true
    String regex2 = ".*[0-9].*";
    boolean result4 = str.matches(regex2);
    //判断是否为纯中文，不是返回false
    String regex3 = "[\\u4e00-\\u9fa5]+";
    boolean result5 = str.matches(regex3);
    System.out.println(result1 + "--" + result2 + "--" + result3
            + "--" + result4 + "--" + result5 + "--" + result6);
}

中英文姓名判斷

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public class HelloWorld{
    public static void main(String[] args) {

        String id = "A123456789";

        System.out.println(maskName("黃藥師")); // A1*****789
        System.out.println(maskName("Hello World")); // A1234*****
        System.out.println(maskName("Huang d")); // ####456789

    }


    public static String maskName(String name){

        String result = "";
        if (isEnglish(name)) {
            result = mask(name, 2, name.length()-3, '*');
        }else{
            result = mask(name, 1, name.length()-2, '*');
        }
        return result;
    }

     //判断是不是英文字母
     public static boolean isEnglish(String charaString) {
         if( charaString == null && "".equals(charaString)){
             return false;
         }
      return charaString.substring(0,1).matches("^[a-zA-Z]*");
     }
    /**
     * 字串遮罩
     * @param text 原始字串
     * @param start 遮罩起始位置index
     * @param length 遮罩長度
     * @param maskSymbol 遮罩符號
     * @return 遮罩過的字串
     */
    private static String mask(String text, int start, int length, char maskSymbol) {
        if (text == null || text.isEmpty()) {
            return "";
        }
        if (start < 0) {
            start = 0;
        }
        if (length < 1) {
            return text;
        }

        StringBuilder sb = new StringBuilder();
        char[] cc = text.toCharArray();
        for (int i = 0; i < cc.length; i++) {
            if (i >= start && i < (start + length)) {
                sb.append(maskSymbol);
            } else {
                sb.append(cc[i]);
            }
        }
        return sb.toString();
    }
}

遮罩長度可以改

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public static String maskName(String name){

    String result = "";
    if (isEnglish(name)) {
        result = mask(name, 2, name.length()-3 > 8 ? 8 : name.length()-3 , '*');
    }else{
        result = mask(name, 1, name.length()-2 > 8 ? 8 : name.length()-2 , 'o');
    }
    return result;
}

sql 判斷方法

oracle 判断字符是否为字母，oracle字符_数据库前沿资讯 | 和通数据库
How to mask characters with X in a varchar2 field in Oracle SQL - Stack Overflow

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--- postgressql
select substr(a.name,1,2)|| repeat('*',length(a.name)-2)|| substr(a.name,length(a.name)-1,2),a.name,ascii(substring(a.name,1,1)) between 65 and 122,
CASE WHEN ascii(substring(a.name,1,1)) between 65 and 122 then 
 substr(a.name,1,2)|| repeat('*',length(a.name)-3)|| substr(a.name,-1,1)
else 
 substr(a.name,1,1)|| repeat('*',length(a.name)-2)|| substr(a.name,-1,1)
end as mask_name,length(a.name)
from account  a
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--oracle
        select substr(full_name,1,5) || regexp_replace(substr(full_name,6,5), '[^ ]', 'X') ||
       substr(full_name,11,5) || regexp_replace(substr(full_name,16,5), '[^ ]', 'X') ||
       substr(full_name,21,5) || regexp_replace(substr(full_name,26,5), '[^ ]', 'X') as masked_name
from
(  
  select 'Tristram Vladimir Chan ' as full_name from dual
)